0,75x^2+13x+24=0

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Solution for 0,75x^2+13x+24=0 equation: 



0.75x^2+13x+24=0

a = 0.75; b = 13; c = +24;
Δ = b2-4ac
Δ = 132-4·0.75·24
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{97}}{2*0.75}=\frac{-13-\sqrt{97}}{1.5}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{97}}{2*0.75}=\frac{-13+\sqrt{97}}{1.5}
$

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